TheKoala73

speaking of it, I need to change one or two master passwords, too… 🙈

afaik it’s not uncommon for software to generate mnemonic passcodes at least that long. Brave browser uses a 25 word phrase for its sync chain, e.g. But I guess you’re right: if I had to think of a mnemonic passcode, I probably wouldn’t use more than 4 or 5 words either…

If I did the maths right, you would need a mnemonic passcode of 9 words out of our dictionary of 5000 words to be at least as strong as our password with 18 characters out of 60 possible unique characters. (It’s closer to 8.6 words, but we obviously can’t allow fractions of words…)

Using our 5000 words dictionary, a 4-word mnemonic passcode would be equivalent to a password with between 8-9 characters and a 5-word mnemonic passcode would be equivalent to a password with between 10-11 characters.

As far as I know, the character used to separate the words/symbols is irrelevant, so whether you use “word-word-word” or “word word word” or “word.word,word” would be the same. Also, if you slightly modify a word (e.g. by replacing al letter with a digit), that shouldn’t make a difference. Correct me if I’m wrong. What I don’t know is what happens if you add a number as an extra symbol.

I also did some calculations using English words as dictionary (although the number of English words is quite difficult to determine because it makes a huge difference what dictionary you use). To get a rough estimate of the numbers I have tried to stick to the rule that a word should be in the official Scrabble dictionary for my web search. These are the rough numbers I found: 1000 3-letter words, 4000 4-letter words, 15000 5-letter words, 23000 6-letter words, 35000 7-letter words and 42000 8-letter words. That would give us a dictionary of about 20000 English words with up to 5 letters and about 120000 English words with up to 8 letters.

Based on that, the mnemonic passcode would have to have 8 words (out of the 20000) and 7 words (out of the 120000) to be at least as strong as our 18 character password. Or, based on the 120000 English words with up to 8 letters, a 4-word passcode would be equivalent to a password with 11-12 characters and a 5-word passcode would be equivalent to a password with 14-15 characters.

Edit: spelling

At work we have both, Edge and Chrome, and there actually are minor differences (that might well result from differences in the pushed settings, though). Like, when using our ticketing system, Edge loses the connection to the server after a period of inactivity and Chrome doesn’t. Also, Chrome seems to be a little faster with script processing (subjectively, have never measured…). But otherwise, they’re basically the same, just as you said.

I’d say Virtualbox should be a good fit. I’m using it myself, mainly to quickly set up VMs for trying out new stuff, most recently Kubuntu and Manjaro distros.

I don’t know UTM. I’ve used Parallels before but it’s just not worth the cost for what I need it for. Then there’s VMware of course, which apparently also has free licenses for personal use. But since I’m happy with Virtualbox, I don’t think I’m going to use anything else anytime soon.